Integrand size = 12, antiderivative size = 57 \[ \int (1-\sin (c+d x))^n \, dx=\frac {2^{\frac {1}{2}+n} \cos (c+d x) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {1}{2}-n,\frac {3}{2},\frac {1}{2} (1+\sin (c+d x))\right )}{d \sqrt {1-\sin (c+d x)}} \]
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Time = 0.01 (sec) , antiderivative size = 57, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.083, Rules used = {2730} \[ \int (1-\sin (c+d x))^n \, dx=\frac {2^{n+\frac {1}{2}} \cos (c+d x) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {1}{2}-n,\frac {3}{2},\frac {1}{2} (\sin (c+d x)+1)\right )}{d \sqrt {1-\sin (c+d x)}} \]
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Rule 2730
Rubi steps \begin{align*} \text {integral}& = \frac {2^{\frac {1}{2}+n} \cos (c+d x) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {1}{2}-n,\frac {3}{2},\frac {1}{2} (1+\sin (c+d x))\right )}{d \sqrt {1-\sin (c+d x)}} \\ \end{align*}
Result contains higher order function than in optimal. Order 9 vs. order 5 in optimal.
Time = 0.07 (sec) , antiderivative size = 49, normalized size of antiderivative = 0.86 \[ \int (1-\sin (c+d x))^n \, dx=-\frac {2^n B_{\frac {1}{2} (1-\sin (c+d x))}\left (\frac {1}{2}+n,\frac {1}{2}\right ) \sqrt {\cos ^2(c+d x)} \sec (c+d x)}{d} \]
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\[\int \left (1-\sin \left (d x +c \right )\right )^{n}d x\]
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\[ \int (1-\sin (c+d x))^n \, dx=\int { {\left (-\sin \left (d x + c\right ) + 1\right )}^{n} \,d x } \]
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\[ \int (1-\sin (c+d x))^n \, dx=\int \left (1 - \sin {\left (c + d x \right )}\right )^{n}\, dx \]
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\[ \int (1-\sin (c+d x))^n \, dx=\int { {\left (-\sin \left (d x + c\right ) + 1\right )}^{n} \,d x } \]
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\[ \int (1-\sin (c+d x))^n \, dx=\int { {\left (-\sin \left (d x + c\right ) + 1\right )}^{n} \,d x } \]
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Timed out. \[ \int (1-\sin (c+d x))^n \, dx=\int {\left (1-\sin \left (c+d\,x\right )\right )}^n \,d x \]
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